Question

A screw gauge has a least count equal to 0.0005 mm. The spindle of the gauge advances 0.1 mm, when the screw is turned through 2 revolutions. Then the thimble of the screw gauge contains _____ divisions .

• A. 50
• B. 100
• C. 150
• D. 200

Answer 1

The correct option is B 100

Pitch of the screw gauge $P=\frac{0.1mm}{2}=0.05mm$

Least count of the screw gauge $L.C.=0.0005mm$

Number of divisions $N=\frac{P}{L.C.}=\frac{0.05}{0.0005}=100$