A screw gauge has a pitch equal to 0.1 mm, How many divisions must be there on its head so as to measure accurately upto 0.0005 mm?

200

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100

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500

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1000

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Solution

The correct option is A 200
Pitch $P = 0.1 m m$
Least count of screw gauge $L . C = 0.0005 m m$
Number of divisions $N = \frac{P}{L . C} = \frac{0.1 m m}{0.0005 m m} = 200$

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A screw gauge has a pitch equal to 0.1 mm, How many divisions must be there on its head so as to measure accurately upto 0.0005 mm?

The correct option is A 200Pitch P=0.1 mmLeast count of screw gauge L.C=0.0005 mmNumber of divisions N=PL.C=0.1 mm0.0005 mm=200

The correct option is A 200
Pitch $P = 0.1 m m$
Least count of screw gauge $L . C = 0.0005 m m$
Number of divisions $N = \frac{P}{L . C} = \frac{0.1 m m}{0.0005 m m} = 200$