A screw gauge has pitch of $1.0 m m$ & $80$ divisions on its circular scale. When a coin is fitted between its studs, it reads $8$ main scale divisions & $48$ divisions on circular scale, with no zero error. The reading of screw gauge is

8.6 m m

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8.48 m m

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8.80 m m

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8.32 m m

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Solution

The correct option is A $8.6 m m$
Reading = $M . S . R + C . S . R$
$= 8 m m + 48 \times l e a s t c o u n t$
$= 8 + 48 \times \frac{1}{80} {l e a s t c o u n t = \frac{pitch}{no. of circular scale divisions}}$
$= 8 + 0.6$
$= 8.6 m m$

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A screw gauge has pitch of 1.0 mm & 80 divisions on its circular scale. When a coin is fitted between its studs, it reads 8 main scale divisions & 48 divisions on circular scale, with no zero error. The reading of screw gauge is

The correct option is A 8.6 mmReading = M.S.R+C.S.R =8mm+48×least count =8+48×180{least count=pitchno. of circular scale divisions} =8+0.6 =8.6 mm

A screw gauge has pitch of $1.0 m m$ & $80$ divisions on its circular scale. When a coin is fitted between its studs, it reads $8$ main scale divisions & $48$ divisions on circular scale, with no zero error. The reading of screw gauge is

The correct option is A $8.6 m m$
Reading = $M . S . R + C . S . R$
$= 8 m m + 48 \times l e a s t c o u n t$
$= 8 + 48 \times \frac{1}{80} {l e a s t c o u n t = \frac{pitch}{no. of circular scale divisions}}$
$= 8 + 0.6$
$= 8.6 m m$