Question

A screw gauge has the least count of $0.01\text{mm}$ and there are $\text{50}$ divisions in its circular scale. The pitch of the screw gauge is :

Answer 1

Given,
$\text{Least Count}=0.01\text{mm}$
$\text{No of division}=50$

$\text{Least Count}$ $=\frac{\text{Pitch}}{\text{No of division on circular scale}}$

$\Rightarrow \text{Pitch}=\text{Least Count}\times \text{No of division on circular scale}$
$\Rightarrow \text{Pitch}=\text{0.01}$$\times$$\text{50}$
$\Rightarrow \text{Pitch}=0.5\text{mm}$

Hence, option $\left(\text{A}\right)$ is the right choice.