A screw gauge, when closed without anything in between it, shows reading as shown below. Determine the zero correction for it if the least count of the screw gauge is 0.01 mm.

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Solution

As the zero of the head scale lies below the pitch scale axis, the zero error is positive.

Zero Error = + (n $\times$ L.C) = + (2 $\times$ L.C) = + (2 $\times$ 0.01) mm = + 0.02 mm

Hence, Zero Correction = – 0.02 mm

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A screw gauge, when closed without anything in between it, shows reading as shown below. Determine the zero correction for it if the least count of the screw gauge is 0.01 mm.

As the zero of the head scale lies below the pitch scale axis, the zero error is positive. Zero Error = + (n × L.C) = + (2 × L.C) = + (2 × 0.01) mm = + 0.02 mm Hence, Zero Correction = – 0.02 mm

As the zero of the head scale lies below the pitch scale axis, the zero error is positive.

Zero Error = + (n $\times$ L.C) = + (2 $\times$ L.C) = + (2 $\times$ 0.01) mm = + 0.02 mm

Hence, Zero Correction = – 0.02 mm