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Question

# A screw gauge with a pitch of 0.5 mm and a circular scale with 50 divisions is used to measure the thickness of a thin sheet of aluminium. What is the thickness of the sheet if the main scale reading is 0.4 mm and 17th division on the circular scale coincides with the main scale line?

A
0.55 mm
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B
0.56 mm
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C
0.57 mm
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D
0.58 mm
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Solution

## The correct option is C 0.57 mmWe firstly need to calculate the least count of the screw gauge. The Least count LS of the screw gauge is given by LC=PitchNo. of divisions on circular scale LC=0.5 mm50=0.01 mm We know that Measured value (MV)= Main scale reading (MSR) + Circular scale reading (CSR) Here, main scale reading, MSR=0.4 mm And we know that Circular scale reading = circular scale division × the least count ⇒CSR=17×0.01 mm=0.17 mm So, Measured value =(0.4+0.17) mm=0.57 mm So, option (c) is the correct choice.

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