A scuba diver is searching for rare jelly fish. Find the depth at which the pressure exerted by water is equal to the atmospheric pressure. Take, $ρ_{w} = 1000 k g / m^{3}$ and $g = 9.8 m / s^{2}$ . Take atmospheric pressure as 101325 Pa.

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Solution

Given:
Atmospheric pressure, $P_{o} = 101325 P a$
Acceleration due to gravity, $g = 9.8 m / s^{2}$
Density of water, $ρ_{w} = 1000 k g / m^{3}$
Pressure exerted by water is equal to the atmospheric pressure.

Pressure exerted by water is:
$P_{w} = ρ_{w} g h$

As the pressure exerted by water is equal to atmospheric pressure,
$P_{w} = P_{o}$
$ρ_{w} g h = P_{o}$
$1000 \times 9.8 \times h = 101325$
$h \approx 10.33 m$

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A scuba diver is searching for rare jelly fish. Find the depth at which the pressure exerted by water is equal to the atmospheric pressure. Take, ρw=1000 kg/m3 and g=9.8 m/s2. Take atmospheric pressure as 101325 Pa.

A scuba diver is searching for rare jelly fish. Find the depth at which the pressure exerted by water is equal to the atmospheric pressure. Take, $ρ_{w} = 1000 k g / m^{3}$ and $g = 9.8 m / s^{2}$ . Take atmospheric pressure as 101325 Pa.