A sealed tank containing a liquid of density ρ moves with horizontal acceleration a as shown in the figure. The difference in pressure between two points A and B will be
A
hρg
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B
lρg
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C
hρg−lρa
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D
hρg+lρa
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Solution
The correct option is Dhρg+lρa The points A and C are in same horizontal level. Hence, PC−PA=ρal Now, PB−PC=ρgh ⇒PB=(PA+ρal)+ρgh⇒PB−PA=hρg+lρa