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Question

A second-degree curve inscribing the ΔABC, where the sides AB,BC and CA have the equations L1L2+λL2L3+μL3L1=0, where λ and μ are parameters. Let the equations of AB,BC and CA be y=2x,y+2x=0, x=1, respectively.
The circumcentre of the ΔABC is:

A
(54,58)
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B
(52,0)
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C
(0,54)
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D
(54,58)
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Solution

The correct option is D (52,0)
Given that L1:y=2x
L2:y=2x
L3:x=1
L1L2+λL2L3+μL3L1=0
(y2x)(y+2x)+λ(y+2x)(x1)+μ(y2x)(x1)=0
(2λ2μ4)x2+y2+(λ+μ)xy+2(μλ)x=0
Since, above equation is circle with center ((λμ),0)
Therefore, 2λ2μ4=1 and λ+μ=0
λμ=52
Therefore, circumcentre is (52,0)
Ans: B

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