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Simple Harmonic Oscillation

A second pend...

Question

A second pendulum is moved to moon where acceleration due to gravity is 1/ 6times that of earth the leght of second s pendulum on moon will be

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Similar questions

Q. A seconds pendulum is moved to moon where acceleration due to gravity is

1 / 6

times that of the earth, the length of the second pendulum on moon w.r.t length on earth would be:

Q. The acceleration due to gravity on a planet is

3 / 2

times that on the earth. If length of a seconds pendulum on earth is

1

m, length of seconds pendulum on the planet is

Q. The time period of a second's pendulum on the surface of moon is found to be

5 s

. The acceleration due to gravity on the surface of moon is:

Q. The mass of earth is

80

times that of moon and its diameter is double that of moon. If the value of acceleration due to gravity on earth is

9.8 m / s^{2}

, then the value of acceleration due to gravity on moon will be

Q. The acceleration due to gravity on the surface of the moon is

1.7 m s^{- 2}

. The time period of a simple pendulum on the moon if its time period on the earth is

3.5

g = 9.8 m s^{- 2})

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