A second square is drawn taking its side length equal to the diagonal of a given square. The ratio of the areas of 1 $^{s t}$ to the 2 $^{n d}$ square is -

1 : 2

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1 : 1

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1 : 3

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1 : 4

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1 : 5

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Solution

The correct option is A
1 : 2

$\frac{d^{2}}{{(\sqrt{2} d)}^{2}} = \frac{d^{2}}{2 d^{2}} = \frac{1}{2}$

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A second square is drawn taking its side length equal to the diagonal of a given square. The ratio of the areas of 1st to the 2nd square is -

The correct option is A 1 : 2 d2(√2d)2=d22d2=12

A second square is drawn taking its side length equal to the diagonal of a given square. The ratio of the areas of 1 $^{s t}$ to the 2 $^{n d}$ square is -

The correct option is A
1 : 2

$\frac{d^{2}}{{(\sqrt{2} d)}^{2}} = \frac{d^{2}}{2 d^{2}} = \frac{1}{2}$