A seconds pendulum is suspended in an elevator moving with constant speed downward direction.The periodic time (T) of that pendulum is...........

Less than two seconds

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Equal to two seconds

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Greater than two seconds

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Very much greater than two seconds

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Solution

The correct option is B Equal to two seconds
$\begin{matrix} T = 2 π \sqrt{\frac{l}{g_{effective}}} T = 2 π \sqrt{\frac{l}{g}} = 2 s \end{matrix}$

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A seconds pendulum is suspended in an elevator moving with constant speed downward direction.The periodic time (T) of that pendulum is...........

The correct option is B Equal to two secondsT=2π√lgeffective T=2π√lg=2s

The correct option is B Equal to two seconds
$\begin{matrix} T = 2 π \sqrt{\frac{l}{g_{effective}}} T = 2 π \sqrt{\frac{l}{g}} = 2 s \end{matrix}$