A section of a solid circular shaft with diameter D is subjected to bending moment M and torque T. The expression for maximum principal stress at the section is
A
2M+TπD3
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B
16πD3(M+√M2+T2)
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C
16πD3(√M2+T2)
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D
16πD3(M+√M2+T2)
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Solution
The correct option is D16πD3(M+√M2+T2) Principal stresses,
σ1/σ2=16πD3[M±√M2+T2]
Maximum principal stress is obtained by chosing '+' sign and minimum principal stress is obtained by '-' sign.