Question

A sector of a circle with radius $10cm$ has central angle ${72}^o$. Find the area of the sector. $(\pi =3.14)$

Answer 1

Given, radius, $r=10cm$, central angle, $\theta ={72}^o$, $\pi =3.14$
Area of sector $=\frac{\theta }{{360}^o}\times \pi r^2$
$=\frac{{72}^o}{{360}^o}\times 3.14\times 10\times 10$
$=\frac{72\times 314}{360}$
$=\frac{314}{5}$
$=62.8$
$\therefore$ The area of sector is $62.8{cm}^2$.