Question

A sector of a circle with radius $12$ $cm$ has central angle ${60}^o$. Find the area of the sector. $(\pi =3.14)$.

Answer 1

Given, radius, $r=12$ $cm$, central angle, $\theta ={60}^o$, $\pi =3.14$
Area of sector $=\frac{\theta }{{360}^o}\times \pi r^2$
$=\frac{{60}^o}{{360}^o}\times 3.14\times 12\times 12$
$=3.14\times 24$
$=75.36$
$\therefore$ The area of sector is $75.36{cm}^2$.