A seepage flow condition is shown in the figure- The saturated unit weight of the soil - sat-18 kN-m3- Using unit weight of water- - w-9-81 kN-m3- the effective vertical stress expressed in kN-m2 on plane X-X is

Force = h_vγ _w h_L at X X = 36× 5=2.5γ _w Effective stress at X X , = 5γ _sub+2.5γ _w = 5(18 9.81)+2.5 × 9.81 = 65.475 kN/m^2 ...

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Soil Mechanics

Effect of Seepage Pressure on Effective Stress

A seepage flo...

Question

A seepage flow condition is shown in the figure. The saturated unit weight of the soil $γ_{s a t} = 18 k N / m^{3}$ . Using unit weight of water, $γ_{w} = 9.81 k N / m^{3}$ , the effective vertical stress (expressed in $k N / m^{2}$ ) on plane X-X is

65.475

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Solution

The correct option is A 65.475
Force = $h_{v} γ_{w}$

$h_{L} a t X - X = \frac{3}{6} \times 5 = 2.5 γ_{w}$

Effective stress at X - X ,

= $5 γ_{s u b} + 2.5 γ_{w}$

= 5(18 - 9.81)+2.5 $\times$ 9.81

= 65.475 $k N / m^{2}$

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A seepage flow condition is shown in the figure. The saturated unit weight of the soil γsat=18 kN/m3. Using unit weight of water, γw=9.81 kN/m3, the effective vertical stress (expressed in kN/m2) on plane X-X is 65.475

The correct option is A 65.475Force = hvγw hL atX−X=36×5=2.5γw Effective stress at X - X , = 5γsub+2.5γw = 5(18 - 9.81)+2.5 × 9.81 = 65.475 kN/m2

A seepage flow condition is shown in the figure. The saturated unit weight of the soil $γ_{s a t} = 18 k N / m^{3}$ . Using unit weight of water, $γ_{w} = 9.81 k N / m^{3}$ , the effective vertical stress (expressed in $k N / m^{2}$ ) on plane X-X is

65.475

The correct option is A 65.475
Force = $h_{v} γ_{w}$

$h_{L} a t X - X = \frac{3}{6} \times 5 = 2.5 γ_{w}$

Effective stress at X - X ,

= $5 γ_{s u b} + 2.5 γ_{w}$

= 5(18 - 9.81)+2.5 $\times$ 9.81

= 65.475 $k N / m^{2}$