Question

A self-fertilizing trihybrid plant forms

• A. 8 different gametes and 64 different zygotes
• B. 4 different gametes and 16 different zygotes
• C. 8 different gametes and 16 different zygotes
• D. 8 different gametes and 32 different zygotes

Answer 1

The correct option is A 8 different gametes and 64 different zygotes

A self-fertilising trihybrid plant will have, n = 3.
The number of combinations of gametes = 2${}^n$. That is equal to 2${}^3$ = 8 combinations.
With one row or column for each allele combination, the total number of boxes in a Punnett Square equals the number of rows times the number of columns. Multi-trait Punnett squares are large. A three trait square has 64 boxes. A four trait square will thus have 256 boxes.

So, the correct answer is option A.