A semi circular wire of mass m is hinged at its top on a vertical wall. What is the horizontal force exerted by the wall on the lower end.

No worries! We‘ve got your back. Try BYJU‘S free classes today!

\frac{6 m g}{π}

No worries! We‘ve got your back. Try BYJU‘S free classes today!

\frac{4 m g}{π}

No worries! We‘ve got your back. Try BYJU‘S free classes today!

none of these

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

Open in App

Solution

The correct option is D none of these
correct option is (D) As we know;
Wire is in equilibrium $s o, τ_{n e t} = 0$
Centre of mass of semi-circular wire is $\frac{2 R}{π}$ where gravitational force acts.

Hence,
$\begin{matrix} mg \times \frac{2 R}{π} & = N \times 2 R m g /_{π} & = N \end{matrix}$

Suggest Corrections

Similar questions

Q. A block of mass m is projected on a smooth horizontal circular track with velocity v. What is the average normal force exerted by the circular walls on the block during its motion from A to B?

Q. A block of mass

m

is projected on a smooth horizontal circular track with speed

v

. What is the average normal force (in Newtons) exerted by circular walls on the block during its motion from

A

B

Q. A uniform rod of mass

m

and length

l

is hinged at its upper end. It is released from a horizontal position. When it becomes vertical, what force does it exert on the hinge ?

Q. A uniform rod of mass m is hinged at its upper end. it is released from the horizontal position. When it reached the vertical position, determine the force does it exert on the hinge?

A block of mass $2 k g$ is pushed against a rough vertical wall with a force of $40 N$ , coefficient of static friction being $0.5$ . Another horizontal force of $15 N$ , is applied on the block in a direction parallel to the wall. Will the frictional force exerted by the wall on the block ?

Join BYJU'S Learning Program

A semi circular wire of mass m is hinged at its top on a vertical wall. What is the horizontal force exerted by the wall on the lower end.

The correct option is D none of thesecorrect option is (D) As we know; Wire is in equilibrium so,τnet=0 Centre of mass of semi-circular wire is 2Rπ where gravitational force acts. Hence, mg×2Rπ=N×2Rmg/π=N