CameraIcon
CameraIcon
SearchIcon
MyQuestionIcon
MyQuestionIcon
1
You visited us 1 times! Enjoying our articles? Unlock Full Access!
Question

A sequence b0,b1,b2, is defined by letting b0=5 and bk=4+bk1 for all natural numbers k. Then which of the following is/are correct?
(Solve using mathematical induction)

A
b4b3=4
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
B
b5b3=10
No worries! We‘ve got your back. Try BYJU‘S free classes today!
C
bn=4n+5
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
D
bn=5n+4
No worries! We‘ve got your back. Try BYJU‘S free classes today!
Open in App
Solution

The correct option is C bn=4n+5
From mathematical induction : the given sequence is true for k=1,2,3,
For k=1,b1=4+b0=4+5
For k=2,b2=4+b1=4+(4+5)=24+5
for k=3,b=3=4+b2=34+5
As, the sequence is true for k=1,2,3
Let P(n):bn=4n+5 is true for k=n
Now, for k=n+1:
p(n+1)=bn+1=4+bn
bn+1=4+4n+5=4(n+1)+5
which is also true for k=n+1
bn=4n+5 is true for all nN

flag
Suggest Corrections
thumbs-up
1
Join BYJU'S Learning Program
Join BYJU'S Learning Program
CrossIcon