1
You visited us 1 times! Enjoying our articles? Unlock Full Access!
Question

# A sequence is a function whose domain is the set of natural number. A sequence s1,s2... of real numbers is said to have a limit l if limn→∞sn=l. If l<∞, then <sn> is said to convergent. The following are well known(i) limn→∞1np=0(p>0)(ii) limn→∞xn=0(|x|<1)(iii) If limn→∞sn=l, then limn→∞s1+s2+...+snn=lLet f(x)=−1+|x−1|,g(x)=2−|x+1| then

A
limnfog(1/n)=0
No worries! We‘ve got your back. Try BYJU‘S free classes today!
B
limnfog(1/n)=1
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
C
limngof(1/n)=0
No worries! We‘ve got your back. Try BYJU‘S free classes today!
D
limngof(1/n)=1
No worries! We‘ve got your back. Try BYJU‘S free classes today!
Open in App
Solution

## The correct option is B limn→∞fog(1/n)=−1fog(x)=⎧⎪ ⎪ ⎪⎨⎪ ⎪ ⎪⎩−(x+3),x<−2x+1,−2≤x≤−1−1−x,−1≤x≤0x−1,x>0gof(x)=⎧⎨⎩1+x,x<−11−x,−1≤x≤03−x,x>0fog(1n)=1n−1→=−1 as n→∞ and gof(1n)=1−1n→=1 as n→∞

Suggest Corrections
0
Join BYJU'S Learning Program
Related Videos
Properties of AP
MATHEMATICS
Watch in App
Explore more
Join BYJU'S Learning Program