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Byju's Answer
Standard XII
Mathematics
Arithmetic Progression
A sequence of...
Question
A sequence of numbers
a
1
,
a
2
,
a
3
,
.
.
.
.
.
satisfies the relation
a
n
+
1
=
a
n
+
a
n
−
1
for
n
≥
2
. Find
a
4
given
a
1
=
a
2
=
1
.
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Solution
A sequence of numbers
a
1
,
a
2
,
a
3
−
−
−
satisfies the relation
a
n
+
1
=
a
n
+
a
n
−
1
n
≥
2
Given,
a
1
=
a
2
=
1
Now,
a
n
+
1
=
a
n
+
a
n
−
1
for
n
=
2
⇒
a
3
=
a
2
+
a
1
∴
a
3
=
2
[Putting the value of
a
1
,
a
2
]
Now,
a
4
=
a
3
+
a
2
∴
a
4
=
2
+
1
∴
a
4
=
3
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0
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1
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