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Question

A sequence x0, x1, x2, x3, ... is defined by letting x0=5 and xk=4+xk-1 for all natural number k.Show that xn=5+4n for all nN using mathematical induction.
[NCERT EXEMPLAR]

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Solution

Given: A sequence x0, x1, x2, x3, ... is defined by letting x0=5 and xk=4+xk-1 for all natural number k.Let Pn: xn=5+4n for all nN.Step I: For n=0,P0: x0=5+4×0=5So, it is true for n=0.Step II: For n=k,Let Pk: xk=5+4k be true for some kN.Step III: For n=k+1,Pk+1: xk+1=4+xk+1-1=4+xk=4+5+4k=5+4k+1So, it is also true for n=k+1.Hence, xn=5+4n for all nN.

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