A serial transmission T1 uses 8 information bits, 2 start bits, 1 stop bit and 1 parity bit for each character. A synchronous transmission T2 uses 3 eight-bit sync characters followed by 30 eight-bit information characters. If the bit rate is 1200 bits/second in both cases, what are the transfer rates of T1 and T2 ?

80 characters/sec, 136 characters/sec

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80 characters/sec, 153 characters/sec

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100 characters/sec, 153 characters/sec

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100 characters/sec, 136 characters/sec

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Solution

The correct option is D 100 characters/sec, 136 characters/sec
$In serial transmission T_{1}$ :
To send 1 character = 8 bit data + 1 + 2 + 1 + 1
= 12 bits
So transfer rate =12 bits
$So transfer rate = \frac{1200 b i t s / s e c}{12 b i t s}$
=100 characters/sec
$In synchronous tranmission T_{2} :$
$To send 30 eight bit = 30 \times 8 = 240 b i t s$
$S y n c h r o n i z e c h a r a c t e r = 3 \times 8 = 24 b i t s$
$So, to send 30 eight bit data = 240 + 24 = 264 b i t s$
So, Transfer rate (for 30 char)
$= \frac{1200 b i t s / s e c}{264 b i t s}$
$= 4.545$ (30 char/sec)
So, In per character $= 4.545 \times 30$
$= 136.2$ character/sec

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