A series is given as: $4 + 7 + 10 + 13 + 16 + . . . . .$ Find the sum of the series up to $10$ terms.

110

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125

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162

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175

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Solution

The correct option is C $175$
The given series is $4 + 7 + 10 + 13 + 16 + . . .$
$a = 4, d = 3$

The sum of series is
$S_{n} = \frac{n}{2} [2 a + (n - 1) d]$

$= \frac{10}{2} [2 (4) + 9 (3)]$
$= 5 (8 + 27)$
$= 5 \times 35$
$= 175$

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