A series LCR circuit has L = 1mH, C = 0.1 μFand R = 10Ω. It is connected across a source of alternating emf of5V but of variable frequency. Find (i) the frequency at which the impedance is minimum (ii) the current atresonance.
A
1052πHz,12A
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
B
1042πHz,12A
No worries! We‘ve got your back. Try BYJU‘S free classes today!
C
1022πHz,12A
No worries! We‘ve got your back. Try BYJU‘S free classes today!
D
1032πHz,12A
No worries! We‘ve got your back. Try BYJU‘S free classes today!
Open in App
Solution
The correct option is A1052πHz,12A Lω=1ωC;ω2=1LC=110−3×10−7 ω=105;f=1052πHz I=VR=510=12A