A series LCR circuit is designed to resonate at an angular frequency -0-105 rad-s- The circuit draws 16 W power from 120 V source at resonance- The value of resistance R in the circuit is -

At resonance, there is no role of inductor and capacitor in the circuit. nbsp; ∴ P=V^2R 16=120^2R ⇒ R=1440016 ⇒ R=900 Ω ...

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Byju's Answer

Standard XII

Physics

Inductor

A series LCR ...

Question

A series $L C R$ circuit is designed to resonate at an angular frequency $ω_{0} = 105 rad/s$ . The circuit draws $16 W$ power from $120 V$ source at resonance. The value of resistance $R$ in the circuit is $Ω$

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Solution

At resonance, there is no role of inductor and capacitor in the circuit.

$∴ P = \frac{V^{2}}{R}$

$16 = \frac{120^{2}}{R}$
$\Rightarrow R = \frac{14400}{16}$

$\Rightarrow R = 900 Ω$

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A series LCR circuit is designed to resonate at an angular frequency ω0=105 rad/s. The circuit draws 16 W power from 120 V source at resonance. The value of resistance R in the circuit is Ω

At resonance, there is no role of inductor and capacitor in the circuit. ∴P=V2R 16=1202R ⇒R=1440016 ⇒R=900 Ω

A series $L C R$ circuit is designed to resonate at an angular frequency $ω_{0} = 105 rad/s$ . The circuit draws $16 W$ power from $120 V$ source at resonance. The value of resistance $R$ in the circuit is $Ω$

At resonance, there is no role of inductor and capacitor in the circuit.

$∴ P = \frac{V^{2}}{R}$

$16 = \frac{120^{2}}{R}$
$\Rightarrow R = \frac{14400}{16}$

$\Rightarrow R = 900 Ω$