A series LCR circuit with L=5H, C=80uF and R=40 ohm is connected to a variable frequency source of 230 V. Determine the resonance frequency of the circuit. Also obtain the impedanceof the circuit and the amplitude of the current at resonance .

Open in App

Solution

$S e r i e s R e s o n a n t F r e q u e n c y = \frac{1}{2 π \sqrt{L C}} = 7.96 H z I m p e d e n c e, Z = \sqrt{[R^{2}} + (ω L - \frac{1}{ω C})^{2} = A t r e s o n a n c e ω L = \frac{1}{ω C} Z = R = 40 o h m A m p l i t u d e a t r e s o n a n c e = 230 V$

Suggest Corrections

Similar questions

Q. Figure 7.21 shows a series LCR circuit connected to a variable frequency 230 V source. L = 5.0 H, C = 80μF, R = 40 W. (a) Determine the source frequency which drives the circuit in resonance. (b) Obtain the impedance of the circuit and the amplitude of current at the resonating frequency. (c) Determine the rms potential drops across the three elements of the circuit. Show that the potential drop across the LC combination is zero at the resonating frequency.

Figure shows a series LCR circuit connected to a variable frequency 230 V source. L = 5.0 H, C = 80

μ

F, R = 40

Ω

(a) Determine the source frequency which drives the circuit in resonance.

(b) Obtain the impedance of the circuit and the amplitude of current at the resonating frequency.

(c) Determine the rms potential drops across the three elements of the circuit. Show that the potential drop across the LC combination is zero at the resonating frequency.

Q. In the given figure, a series

L - C - R

circuits is connected to a variable frequency source of

230 V

. The impedance and amplitude of the current at the resonating frequency will be

Q. Figure shows a series LCR circuit connected to a variable frequency 230 V source.
The source frequency which drives the circuit in resonance is

Q. An LCR series a.c, circuit is connected to an a.c,source of variable angular frequency

ω

and a fixed voltage amplitude. The current amplitude in the circuit is found to be the same for two angular frequencies

ω_{1}

and

ω_{2}

. The resonance angular frequency of this circuit must be

Join BYJU'S Learning Program

A series LCR circuit with L=5H, C=80uF and R=40 ohm is connected to a variable frequency source of 230 V. Determine the resonance frequency of the circuit. Also obtain the impedanceof the circuit and the amplitude of the current at resonance .

Series Resonant Frequency=12πLC=7.96HzImpedence,Z=[R2+(ωL-1ωC)2=At resonance ωL=1ωCZ=R=40ohmAmplitude at resonance=230V

$S e r i e s R e s o n a n t F r e q u e n c y = \frac{1}{2 π \sqrt{L C}} = 7.96 H z I m p e d e n c e, Z = \sqrt{[R^{2}} + (ω L - \frac{1}{ω C})^{2} = A t r e s o n a n c e ω L = \frac{1}{ω C} Z = R = 40 o h m A m p l i t u d e a t r e s o n a n c e = 230 V$