A series R-C combination is connected to an AC voltage of angular frequency -500 rad - s- If the impedance of the R-C circuit is R -1-25 the time constant in milliseconds of the circuit is

The impedance of RC circuit is √(R^2+1/(ω C)^2)=R√(1.25). On simplification, we get time constant RC=2/ω=4× 10^ 3s. ...

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Standard XII

Physics

Time Constant

A series R-C ...

Question

A series R-C combination is connected to an AC voltage of angular frequency $ω$ = 500 rad/s. If the impedance of the R-C circuit is $R \sqrt{1.25}$ the time constant (in milliseconds) of the circuit is

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Solution

The impedance of RC circuit is $\sqrt{R^{2} + 1 / (ω C)^{2}} = R \sqrt{1.25}$ . On simplification, we get time constant $R C = 2 / ω = 4 \times 10^{- 3} s$ .

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A series R-C combination is connected to an AC voltage of angular frequency ω = 500 rad/s. If the impedance of the R-C circuit is R√1.25 the time constant (in milliseconds) of the circuit is

The impedance of RC circuit is √R2+1/(ωC)2=R√1.25. On simplification, we get time constant RC=2/ω=4×10−3s.

A series R-C combination is connected to an AC voltage of angular frequency $ω$ = 500 rad/s. If the impedance of the R-C circuit is $R \sqrt{1.25}$ the time constant (in milliseconds) of the circuit is

The impedance of RC circuit is $\sqrt{R^{2} + 1 / (ω C)^{2}} = R \sqrt{1.25}$ . On simplification, we get time constant $R C = 2 / ω = 4 \times 10^{- 3} s$ .