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Question

A set containing n elements. A subset P of A is chosen. The set A is reconstructed by replacing the element of P. A subset Q of A is again chosen the number of ways of choosing P and Q so that PQ=ϕ is

A
2n2nCn
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B
2n
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C
2n1
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D
3n
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Solution

The correct option is D 3n
Let A= {a1,a2...,an}
For each a1A (1in)
we have the following four cases
i) aiP and aiQ
ii) aiPandaiQ
iii) aiPandaiQ
iv) aiPandaiQ
Thus, the total number of ways of choosing P and Q is 4n.
Out of these four choices, (i) is not favourable for PQ=Q
Thus, the number of ways =3n.

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