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Question

A set of 24 tuning forks are so arranged that each gives 6 beats per second with the previous one. If the frequency of the last tuning fork is double that of the first, frequency of the second turning fork is:

A
138 Hz
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B
144 Hz
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C
132 Hz
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D
276 Hz
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Solution

The correct option is B 144 Hz

According to quest- f1+23(6)=2f1
23(6)=f1
f1=138
f2=f1+6
f2=138+6=144Hz

1176695_943697_ans_2caa69987636440a807155a680be7cff.png

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