A shaft of diameter $20_{- 0.15}^{+ 0.05} m m$ and a hole of diameter $20_{+ 0.10}^{+ 0.20} m m$ when assembled would yield.

None of these

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Transition fit

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Interference fit

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Clearance fit

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Solution

The correct option is D Clearance fit
A shaft of diameter $20_{- 0.15}^{+ 0.05} m m$ and a hole of diameter $20_{+ 0.10}^{+ 0.20} m m$ when assembled would be Clearance fit

Suggest Corrections

Similar questions

20_{- 0.15}^{+ 0.05} m m

20_{+ 0.10}^{+ 0.20} m m

40_{+ 0.000}^{+ 0.000}

4_{- 0.010}^{+ 0.010}

A shaft of {20.00}_{- 0.005}^{+ 0.015} m m diameter

A hole of {20.00}_{+ 0.025}^{- 0.010} m m diameter

70_{+ 0.12}^{+ 0.00}

70_{- 0.10}^{- 0.22}

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