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Standard XII

Physics

Equipartition Theorem

A sheet of ...

Question

A sheet of $15.0 g$ of gold at $25.0 C$ is placed on a $30.0 g$ sheet of copper at $45.0 C$ . What is the final temperature of the two metals assuming that no heat is lost to the surroundings. The specific heats of gold and copper are $0.129 J / g C$ and $0.385 J / g C$ respectively.

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Solution

Heat lost copper = heat gain by gold
$30 \times 0.385 (318 - T) = 15 \times 0.129 (T - 298)$
final temperature $T = 315.1 K$
$T = 42.1 C$

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A sheet of 15.0g of gold at 25.0C is placed on a 30.0g sheet of copper at 45.0C. What is the final temperature of the two metals assuming that no heat is lost to the surroundings. The specific heats of gold and copper are 0.129J/gC and 0.385J/gC respectively.

Heat lost copper = heat gain by gold30×0.385(318−T)=15×0.129(T−298)final temperature T=315.1K T=42.1C

A sheet of $15.0 g$ of gold at $25.0 C$ is placed on a $30.0 g$ sheet of copper at $45.0 C$ . What is the final temperature of the two metals assuming that no heat is lost to the surroundings. The specific heats of gold and copper are $0.129 J / g C$ and $0.385 J / g C$ respectively.

Heat lost copper = heat gain by gold
$30 \times 0.385 (318 - T) = 15 \times 0.129 (T - 298)$
final temperature $T = 315.1 K$
$T = 42.1 C$