A sheet of aluminium foil of negligible thickness is introduced between the plates of a capacitor. The capacitance of the capacitor

decreases

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remains unchanged

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becomes infinite

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increases.

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Solution

The correct option is B remains unchanged
The capacitance without aluminium foil is $C = \frac{A ϵ_{0}}{d}$
The capacitance with aluminium foil is $C^{'} = \frac{A ϵ_{0}}{d - t}$
If thickness $(t)$ of foil is negligible so $d - t \sim d .$ Hence, $C = C^{'}$

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A sheet of aluminium foil of negligible thickness is introduced between the plates of a capacitor. The capacitance of the capacitor

The correct option is B remains unchangedThe capacitance without aluminium foil is C=Aϵ0d The capacitance with aluminium foil is C′=Aϵ0d−tIf thickness (t) of foil is negligible so d−t∼d. Hence, C=C′

The correct option is B remains unchanged
The capacitance without aluminium foil is $C = \frac{A ϵ_{0}}{d}$
The capacitance with aluminium foil is $C^{'} = \frac{A ϵ_{0}}{d - t}$
If thickness $(t)$ of foil is negligible so $d - t \sim d .$ Hence, $C = C^{'}$