wiz-icon
MyQuestionIcon
MyQuestionIcon
1
You visited us 1 times! Enjoying our articles? Unlock Full Access!
Question

A shell acquires the initial velocity v = 320 m/s, having made n = 2.0 turns inside the barrel whose length is equal to l = 2.0 m. Assuming that the shell moves inside the barrel with a uniform acceleration, find the angular velocity of its axial rotation, at the moment when the shell escapes the barrel.


A

No worries! We‘ve got your back. Try BYJU‘S free classes today!
B

No worries! We‘ve got your back. Try BYJU‘S free classes today!
C

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
D

Data insufficient

No worries! We‘ve got your back. Try BYJU‘S free classes today!
Open in App
Solution

The correct option is C


When the shell comes out if acquires the velocity of 320 m/s.

u = 0

v = 320

s = 2 m

v2 = u2 + 2as

(320)2 = 2.a.2

a=(160)2

V = u + at

320 = (160)2 t

t = (180)sec

Now in this time the shell has rotated twice.

This means each and every point would have made one angular displacement of

θ = 4π

ω0 = 0

f = 180

θ = ω0t + 12a t2

4π = 12a(180)2

a = 8π × (80)2

ωt = ω0 + a t

ωt = 8π × (80)2 × 180

= 640π

ω = 2010 radsec


flag
Suggest Corrections
thumbs-up
0
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
All Strings Attached
PHYSICS
Watch in App
Join BYJU'S Learning Program
CrossIcon