Question

A shell fired from a canon making an angle $\theta$ with horizontal explodes in two equal parts at the highest point of its path. One of the part retraces the path of the shell towards canon with the original speed v, then the velocity of the remaining part in $m/s$ just after the explosion is-

• A. $3v\cos \theta$
• B. $2v\cos \theta$
• C. $\left(3/2\right)v\cos \theta$
• D. $\left(\sqrt{3}/2\right)v\cos \theta$

Answer 1

The correct option is A $3v\cos \theta$

Let $v^{\prime }$ be the velocity of second fragment from conservation of linear momentum.
$2m\left(v\cos \theta \right)=m{v}^{\prime }-mv\cos \theta \Rightarrow v^{\prime }=3v\cos \theta$