A shell initially at rest explodes into two pieces of unequal masses. Then the two pieces will

fly in opposite direction with same velocity

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fly in opposite direction with same kinetic energy

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fly in opposite direction with same momentum

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fly in the same direction with same momentum

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Solution

The correct option is B fly in opposite direction with same momentum
Since no external force is acting on the system then its momentum will be conserved.
So initially shell was at rest hence zero momentum and thus finally two pieces will fly in opposite direction with same momentum to maintain the total momentum equals to zero as before.

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