A shell is fired from a gun from the bottom of a hill along its slope- The slope of the hill is -30- and the angle of the barrel to the horizontal - 60- The initial velocity v of the shell is 21 m - sec- Then distance of point from the gun at which shell will fall A- 20 mB- 30 mC- 10 mD- 40 m

The correct option is B 30 mHere u=21 m/sec, α=30^∘, θ=β α=60^∘ 30^∘=30^∘ Range R=2u^2/gsin θcos(θ+ α)/cos^2α=2× (21)^2×sin 30^∘cos 60^∘/9.8 ×cos^2 30^∘=30 m ...

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Standard XII

Physics

Maximum Range

A shell is fi...

Question

A shell is fired from a gun from the bottom of a hill along its slope. The slope of the hill is $α = 30^{\circ}$ , , and the angle of the barrel to the horizontal $β = 60^{\circ}$ . The initial velocity v of the shell is 21 m/sec. Then distance of point from the gun at which shell will fall

10 m

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20 m

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30 m

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40 m

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Solution

The correct option is C 30 m
$H e r e u = 21 m / s e c, α = 30^{\circ}, θ = β - α = 60^{\circ} - 30^{\circ} = 30^{\circ} R a n g e R = \frac{2 u^{2}}{g} \frac{s i n θ cos (θ + α)}{{cos}^{2} α} = \frac{2 \times (21)^{2} \times sin 30^{\circ} cos 60^{\circ}}{9.8 \times {cos}^{2} 30^{\circ}} = 30 m$

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A shell is fired from a gun from the bottom of a hill along its slope. The slope of the hill is α=30∘, , and the angle of the barrel to the horizontal β=60∘. The initial velocity v of the shell is 21 m/sec. Then distance of point from the gun at which shell will fall

The correct option is C 30 mHere u=21 m/sec, α=30∘,θ=β−α=60∘−30∘=30∘Range R=2u2gsinθcos(θ+α)cos2α=2×(21)2×sin30∘cos60∘9.8×cos230∘=30 m

A shell is fired from a gun from the bottom of a hill along its slope. The slope of the hill is $α = 30^{\circ}$ , , and the angle of the barrel to the horizontal $β = 60^{\circ}$ . The initial velocity v of the shell is 21 m/sec. Then distance of point from the gun at which shell will fall