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Byju's Answer

Standard XII

Physics

2nd Equation of Motion

A shell is fi...

Question

A shell is fired vertically upwards with a velocity $v_{1}$ from a trolley moving horizontally with velocity $v_{2}$ . A person on the ground observes the motion of the shell as a parabola, whose horizontal range is

\frac{2 v_{1}^{2} v_{2}}{g}

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\frac{2 v_{1}^{2}}{g}

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\frac{2 v_{2}^{2}}{g}

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\frac{2 v_{1} v_{2}}{g}

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Solution

The correct option is D $\frac{2 v_{1} v_{2}}{g}$
Vertical velocity of shell $u_{y} = v_{1}$
Horizontal velocity of shell $u_{x} = v_{2}$
Horizontal range of projectile $R = \frac{2 u_{x} u_{y}}{g}$
$⟹ R = \frac{2 v_{1} v_{2}}{g}$

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A shell is fired vertically upwards with a velocity v1 from a trolley moving horizontally with velocity v2. A person on the ground observes the motion of the shell as a parabola, whose horizontal range is

The correct option is D 2v1v2gVertical velocity of shell uy=v1Horizontal velocity of shell ux=v2Horizontal range of projectile R=2uxuyg⟹ R=2v1v2g

A shell is fired vertically upwards with a velocity $v_{1}$ from a trolley moving horizontally with velocity $v_{2}$ . A person on the ground observes the motion of the shell as a parabola, whose horizontal range is

The correct option is D $\frac{2 v_{1} v_{2}}{g}$
Vertical velocity of shell $u_{y} = v_{1}$
Horizontal velocity of shell $u_{x} = v_{2}$
Horizontal range of projectile $R = \frac{2 u_{x} u_{y}}{g}$
$⟹ R = \frac{2 v_{1} v_{2}}{g}$