A shell of radius R having uniform surface change density σCm−2 is divided into two parts as shown in the figure. Find the minimum force F required to keep the two parts together.
A
14σ2πR2ε0
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B
12σ2πR2ε0
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C
18σ2πR2ε0
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D
zero
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Solution
The correct option is B12σ2πR2ε0
Net electrostatic pressure acting at each point on the surface of charge density σ is, Pe=12σ2ε0
There will be a force due to electrostatic pressure on each half surface which should be balanced by F to keep the parts together.
Thus, FA=Pe
where A=πR2 is the projected area where Pe is acting.