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Question

A shell of radius R having uniform surface change density σ Cm2 is divided into two parts as shown in the figure. Find the minimum force F required to keep the two parts together.


A
14σ2πR2ε0
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B
12σ2πR2ε0
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C
18σ2πR2ε0
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D
zero
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Solution

The correct option is B 12σ2πR2ε0

Net electrostatic pressure acting at each point on the surface of charge density σ is,
Pe=12σ2ε0

There will be a force due to electrostatic pressure on each half surface which should be balanced by F to keep the parts together.
Thus, FA=Pe
where A=πR2 is the projected area where Pe is acting.

F=Pe×A=12σ2ε0πR2

Hence, option (b) is the correct answer.

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