Question

A shepherd has 200 sheep with him. Find the number of sheeps with him after 3 years if the increase in number of sheeps is 8% every year.

Answer 1

Here, P = Number of sheeps initially = 200
A = Number of sheeps after 3 years
R = Rate of increase of number of sheeps per year = 8 %
N = 3 years

$$\begin{gathered} \mathrm{A}=\mathrm{P}{\left(1+\frac{\mathrm{R}}{100}\right)}^{\mathrm{N}} \\ =200{\left(1+\frac{8}{100}\right)}^3 \\ =200{\left(1+\frac{2}{25}\right)}^3 \\ =200{\left(\frac{27}{25}\right)}^3 \\ =251.94 \\ =252\left(\mathrm{approx}\right) \end{gathered}$$

Hence, the number of sheeps after 3 years is 252.