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Question

A ship A is moving Westwards with a speed of 10 km h−1 and a ship B 100 km South of A is moving northwards with a speed of 10 km h−1. The time after which the distance between them becomes shortest is

A
0h
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B
5h
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C
52h
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D
102h
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Solution

The correct option is B 5h
It is clear from the diagram that the shortest distance between the ship A and B is PQ.

Here, Sin450=PQOQ

PQ=100×12=502m

Also,

VAB=V2A+V2B=102+102=102km/h

So, the time taken to reach shortest path is

t=PQVAB=502102=5h

1474444_1433877_ans_7e9aabc38a5a4189a0f05bdb0da0bc90.png

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