A ship of mass 3×107kg initially at rest is pulled by a force of 5×104N through a distance of 3m. Assume that the resistance due to water is negligible. The speed of the ship is
A
1.5m/s
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B
60m/s
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C
0.1m/s
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D
5m/s
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Solution
The correct option is C0.1m/s Mass of the ship m=3×107kg
Force on the ship F=5×104N
Using Newton's second law, F=ma ⇒a=5×1043×107=53×10−3m/s2
From 3rd equation of motion, v2−u2=2as and u=0 ⇒v2=2×53×10−3×3⇒v2=10−2⇒v=10−1=0.1m/s