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Standard IX

Physics

Speed of Sound

A ship sends ...

Question

A ship sends a longitudinal wave towards the bottom of the sea. The wave returns from the bottom of the sea after $2.0 s$ . The bulk modulus of the sea water is $2.2 \times 10^{9} N m^{- 2}$ and the density of water is $1.1 g c m^{- 3}$ . The depth of the sea is about

2200 m

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2000 m

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1400 m

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1100 m

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Solution

The correct option is C $1400 m$
$v = \sqrt{\frac{β}{ρ}} = \sqrt{\frac{2.2 \times 10^{9}}{1.1 \times 10^{3}}} = 10^{3} \sqrt{2} m s^{- 1}$
$x = \frac{v t}{2} = \frac{10^{3} \sqrt{2} \times 2}{2} = 1400 m$

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A ship sends a longitudinal wave towards the bottom of the sea. The wave returns from the bottom of the sea after 2.0 s. The bulk modulus of the sea water is 2.2×109 Nm−2 and the density of water is 1.1 g cm−3. The depth of the sea is about

The correct option is C 1400 mv=√βρ=√2.2×1091.1×103=103√2 ms−1x=vt2=103√2×22=1400 m

A ship sends a longitudinal wave towards the bottom of the sea. The wave returns from the bottom of the sea after $2.0 s$ . The bulk modulus of the sea water is $2.2 \times 10^{9} N m^{- 2}$ and the density of water is $1.1 g c m^{- 3}$ . The depth of the sea is about

The correct option is C $1400 m$
$v = \sqrt{\frac{β}{ρ}} = \sqrt{\frac{2.2 \times 10^{9}}{1.1 \times 10^{3}}} = 10^{3} \sqrt{2} m s^{- 1}$
$x = \frac{v t}{2} = \frac{10^{3} \sqrt{2} \times 2}{2} = 1400 m$