A ship travels downstream from point A to a point B in 2 hours and upstream in 3 hours. Then the time taken by log of wood to cover the distance from A to B is

A) 5h. B) 9h. C) 12h. D) 1h.

Explain in detail.

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Solution

Speed of the river- u Speed of the ship - v

Distance= speed*time =x Distance upstream = distance downstream So,

3(v-u)= 2(v+u)= x

Solve to get 5u=v

2(v+u)=x So,

2(5u+u)=x

12u=x

Thus, u=x/12

Hence, the time needed= 12hours

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A ship travels downstream from point A to a point B in 2 hours and upstream in 3 hours. Then the time taken by log of wood to cover the distance from A to B is A) 5h. B) 9h. C) 12h. D) 1h. Explain in detail.

Speed of the river- u Speed of the ship - v Distance= speed*time =x Distance upstream = distance downstream So, 3(v-u)= 2(v+u)= x Solve to get 5u=v 2(v+u)=x So, 2(5u+u)=x 12u=x Thus, u=x/12 Hence, the time needed= 12hours

A ship travels downstream from point A to a point B in 2 hours and upstream in 3 hours. Then the time taken by log of wood to cover the distance from A to B is

A) 5h. B) 9h. C) 12h. D) 1h.

Explain in detail.

Speed of the river- u Speed of the ship - v

Distance= speed*time =x Distance upstream = distance downstream So,

3(v-u)= 2(v+u)= x

Solve to get 5u=v

2(v+u)=x So,

2(5u+u)=x

12u=x

Thus, u=x/12

Hence, the time needed= 12hours