Question

A shopkeeper bought $600$ oranges and $400$ bananas. He found $15\%$ of oranges and $8\%$ of bananas were rotten. Find the percentage of fruits in good condition.

• A. $87.8$%
• B. $80.00$%
• C. $85.00$%
• D. $89.25$%

Answer 1

The correct option is A $87.8$%

Total number of fruits shopkeeper bought$=1000(600+400)$

Number of rotten oranges $=15\%$ of $600=\frac{15}{100}\times 600=90$

Number of rotten bananas $=8\%$ of $40=\frac{8}{100}\times 40=32$

$\therefore$Total number of rotten fruits $=90+32=122$

$\therefore$ Number of fruits in good condition $=1000-122=878$

$\therefore$ Percentage of fruits in good condition $=\frac{878}{1000}\times 100\%$

$=\frac{87800}{1000}\%=87.8\%$