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Question

# A shopkeeper bought 600 oranges and 400 bananas. He found 15% of oranges and 8% of bananas were rotten. Find the percentage of fruits in good condition.

A
87.8%
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B
80.00%
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C
85.00%
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D
89.25%
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Solution

## The correct option is A 87.8%Total number of fruits shopkeeper bought=1000(600+400) Number of rotten oranges =15% of 600=15100×600=90Number of rotten bananas =8% of 40=8100×40=32∴Total number of rotten fruits =90+32=122∴ Number of fruits in good condition =1000−122=878∴ Percentage of fruits in good condition =8781000×100%=878001000%=87.8%

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