A shopkeeper earns a profit of ?3 by selling one apple and incurs a loss of ?2 on an orange.In october,he incurred a loss of ?6.In this period,he sold12 apples. How many oranges did he sell?

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Solution

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$P r o f i t e a r n e d f r o m s e l l i n g o n e a p p l e = R s . 3 = + 3 L o s s i n c u r r e d o n s e l l i n g a n o r a n g e = R s . 2 = - 2 L e t t h e n u m b e r o f o r a n g e s s o l d b y s h o p k e e p e r = x D u r i n g O c t o b e r, t h e s h o p k e e p e r s o l d 12 a p p l e s, s o h e m a d e p r o f i t o f R s . (12 \times 3) = R s . 36 T h e s h o p k e e p e r i n c u r r e d a l o s s o f R s . 6 = - 6 S o, 36 - 2 x = - 6 \Rightarrow 42 = 2 x \Rightarrow x = 21 T h u s, t h e s h o p k e e p e r s s o l d 21 o r a n g e s i n O c t o b e r .$

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