A shopkeeper gives two successive discounts of $20 %$ and $25 %$ to retail purchaser. Calculate the total discount.

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Solution

Total discount $= 100 - 100 \times (1 - \frac{20}{100}) (1 - \frac{25}{100})$
$= 100 - 100 \times \frac{80}{100} \times \frac{75}{100}$
$= 100 - 60$
$= 40$
Therefore, the total discount $= 40 %$ .

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A shopkeeper gives two successive discounts of 20% and 25% to retail purchaser. Calculate the total discount.

Total discount =100−100×(1−20100)(1−25100)=100−100×80100×75100=100−60=40Therefore, the total discount =40%.

A shopkeeper gives two successive discounts of $20 %$ and $25 %$ to retail purchaser. Calculate the total discount.

Total discount $= 100 - 100 \times (1 - \frac{20}{100}) (1 - \frac{25}{100})$
$= 100 - 100 \times \frac{80}{100} \times \frac{75}{100}$
$= 100 - 60$
$= 40$
Therefore, the total discount $= 40 %$ .