Question

A shopkeeper has certain number of eggs of which $5\%$ are found to be broken. He sells $93\%$ of the remainder and still has $266$ eggs left. How many eggs did he originally have?

Answer 1

Suppose the shopkeeper had x eggs, originally

No of broken eggs $5\%ofx$

$Balance=x-\left(\frac{x}{20}\right)=\frac{19x}{20}$

$\%$ of Eggs left after selling $=100\%-93\%=7\%$

$7$ of $\frac{19x}{20}=266$

$\frac{7}{100}\ast \frac{19x}{20}=266$

$x=\frac{266\ast 20\ast 100}{7\ast 19}$

$x=4000$