Question

A shopkeeper has two types of wheat . The percentage of pure wheat first type of wheat is 80% and the percentage of pure wheat in second type of wheat is 60%. If he mixes 28kg of first type of wheat to the 32 kg of second type of wheat , then find the percentage of pure wheat in resultant wheat in the mixture.

Answer 1

Weight of Resultant mixture = 60 Kg

Amount of pure wheat in resultant mixture = $28\times \frac{4}{5}+32\times \frac{3}{5}=$ $41.6Kg$

So Percentage of pure wheat in resultant mixture = $69\frac{{}^1}{{}_3}$%